Querying Teradata and SQL Server - Tutorial 1: The SELECT Statement

Raymond Raymond event 2015-05-03 visibility 50,597 comment 7
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SELECT is one of the most commonly used statements. In this tutorial, I will cover the following items:

  • Two of the principal query clauses—FROM and SELECT
  • Data Types
  • Built-in functions
  • CASE expressions and variations like ISNULL and COALESCE.

* The function names mentioned above are based on SQL Server; Teradata’s equivalent functions may have same or different names.

Prerequisites

Please follow the post below to setup the sample databases in SQL Server and Teradata if you haven’t.

 Querying Teradata and SQL Server - Tutorial 0: Preparation

The From Cause

Task

Retrieve all the employees (EmployeeID, Name, Birthday) from Employee table.

Query – SQL Server

USE [TD_MS_SAMPLE_DB]
GO
SELECT Emp.EmployeeID, Emp.EmployeeName, Emp.Birthday FROM dbo.Employee Emp;

Query – Teradata

DATABASE TD_MS_SAMPLE_DB;
SELECT Emp.EmployeeID,
    Emp.EmployeeName,
    Emp.Birthday
    FROM Employee Emp;

Result

image

Comment

There is no Schema concept in Teradata but Database/User is similar to the schema in SQL Server. Any Teradata USER is also a DATABASE, but not all DATABASEs are USERs.

In Teradata, use ‘DATABASE $DatabaseName;’ statement to set the default database.

The SELECT Clause

Task

Retrieve all the employees (EmployeeID, Name, Birthday Year) from Employee table.

Query – SQL Server

USE [TD_MS_SAMPLE_DB]
GO
SELECT Emp.EmployeeID, Emp.EmployeeName, YEAR(Emp.Birthday) AS 'Birthday Year' FROM dbo.Employee Emp;
-- Or
SELECT Emp.EmployeeID, Emp.EmployeeName, YEAR(Emp.Birthday) AS [Birthday Year] FROM dbo.Employee Emp;

Query – Teradata

DATABASE TD_MS_SAMPLE_DB;
SELECT Emp.EmployeeID,
    Emp.EmployeeName,
   EXTRACT(YEAR FROM Emp.Birthday) AS "Birthday Year"
    FROM Employee Emp;

Result

image

Comments

Teradata supports column alias and they have to enclosed with double quotes if there is a space in the name( you can use single quote or [] in SQL Server).

The date and time functions in Teradata are not all the same as SQL Server:

DATE or CURRENT_DATE -  Both displays current date.
ADD_MONTHS(date,3) - Add 3 months to the current date.
ADD_MONTHS(date, -2)- Subtract 2 months from the current date.
TIME or CURRENT_TIME - Both displays current time.
EXTRACT( Day FROM Date)- Extracts and displays the day.
EXTRACT(Month FROM Date) - Extracts and display month.
EXTRACT(Year FROM Date) - Extracts and displays year.
CURRENT_TIMESTAMP - Displays combination of both date and time.
EXTRACT( Hour FROM Time) - Extracts and displays hour.
EXTRACT( Minute FROM Time) - Extracts and displays Minute.
EXTRACT( Second FROM Time) - Extracts and displays Second.

In Teradata, the column naming standards are different:

  • Uppercase or lowercase letters (A to Z and a to z).
  • Digits (0 through 9).
  • The special characters $, #, and _.
  • Must NOT begin with a digit.
  • Must NOT begin with an UNDER SCORE.
  • NO keywords can be used as aliases.
  • Alias Names can not be duplicated in the same SQL query.
  • Usage of the word AS is optional.
  • If there is a space used, make sure it is enclosed with only double quotes.

In SQL Server, the identifiers must follow the following rules:

  • the first character must be a letter in the range A through Z (lower or uppercase), underscore (_), at sign (@), or number sign (#).
  • Subsequent characters can include letters, decimal numbers, at sign, dollar sign ($), number sign, or underscore.
  • The identifier cannot be a reserved keyword in T-SQL
  • Cannot have embedded spaces, and must not include supplementary characters.
  • An identifier doesn’t comply with these rules must be delimited, e.g. [2015] is an legal identifier.

Data Types

Please refer to the following links to understand all the data types in SQL Server and Teradata.

Both platforms cover the commonly used data types (Exact numerics, Unicode character strings, Approximate numerics, Binary strings, Date and time, Character strings …) while keeping its own extensions/variations.

Identity column

In SQL Server, identity is frequently used. There are multiple choices:

  • The identity column property
  • Sequence object (ANSI standard)
  • UNIQUEIDENTIFIER (NEWID() )
  • NEWSEQUENTIALID

In Teradata, you can also define auto-increased columns.

Query – SQL Server

USE [TD_MS_SAMPLE_DB]
GO
CREATE TABLE TestTable
(
ID INT IDENTITY(1,1) NOT NULL
);

Query – Teradata

DATABASE TD_MS_SAMPLE_DB;
CREATE TABLE TestTable
(
ID INT GENERATED ALWAYS AS IDENTITY (START WITH 1 INCREMENT BY 1 MINVALUE -2147483647 MAXVALUE 2147483647 NO CYCLE) NOT NULL
);

Format

To format data, please refer to the following links:

Date and Time functions

Task

Retrieve all the employees (EmployeeID, Name, Age) from Employee table.

Query – SQL Server

USE [TD_MS_SAMPLE_DB]
GO
SELECT Emp.EmployeeID, Emp.EmployeeName, DATEDIFF(YEAR,Emp.Birthday, CURRENT_TIMESTAMP) AS Age FROM dbo.Employee Emp;

Query – Teradata

DATABASE TD_MS_SAMPLE_DB;
SELECT Emp.EmployeeID,
    Emp.EmployeeName,
    (EXTRACT (YEAR
    FROM CURRENT_TIMESTAMP) - EXTRACT(YEAR
    FROM Emp.Birthday)) AS Age
    FROM Employee Emp;

Result

image

Character Functions

Task

Retrieve the following information from Employee table:

  • EmployeeID
  • EmployeeName
  • EmployeeNameLength (Length of the name)
  • EmployeeNameInitials (The first character of the name)EmployeeJobGradeAndSalary (display as ‘JobGrade -  Salary’, e.g. ‘2 -  150000’)

SQL - SQL Server

USE [TD_MS_SAMPLE_DB]
GO
SELECT Emp.EmployeeID, Emp.EmployeeName, 
LEN(EmployeeName) AS EmployeeNameLength,
SUBSTRING(EmployeeName,1,1) AS EmployeeNameInitials,
CAST(Emp.JobGrade AS VARCHAR(1)) + ' - ' + CAST(Emp.Salary AS VARCHAR(13)) AS EmployeeJobGradeAndSalary
FROM dbo.Employee Emp;

SQL – Teradata

DATABASE TD_MS_SAMPLE_DB;
SELECT Emp.EmployeeID,
    Emp.EmployeeName,
    CHARACTER_LENGTH(EmployeeName) AS EmployeeNameLength,
    SUBSTR(EmployeeName,1,1) AS EmployeeNameInitials,
    CAST(CAST(Emp.JobGrade AS INTEGER)AS VARCHAR(2)) || ' - ' || CAST(Emp.Salary AS VARCHAR(13)) AS EmployeeJobGradeAndSalary
    FROM Employee Emp;

Or

SELECT Emp.EmployeeID,
    Emp.EmployeeName,
    SUBSTRING(EmployeeName
    FROM 1 FOR 1) AS EmployeeNameLength,
        SUBSTR(EmployeeName,1,1) AS EmployeeNameInitials,
        CAST((Emp.JobGrade (FORMAT '9')) AS VARCHAR(1)) || ' - ' || CAST((Emp.Salary (FORMAT '9(3),999.99')) AS VARCHAR(13)) AS EmployeeJobGradeAndSalary
    FROM Employee Emp;

Result

image

Comments

In Teradata, you can also use the following clause for substring:

SUBSTRING (EmployeeName FROM 1 FOR 1) 

For string concatenation, the operator is ‘+’in SQL Server while it is ‘||’in Teradata (same as Oracle).

There are also other similar character functions in Teradata, e.g. UPPER, LOWER, TRIM, LTRIM, RTRIM, LPAD, RPAD… You can find more details at http://www.info.teradata.com/HTMLPubs/DB_TTU_14_00/index.html#page/SQL_Reference/B035_1145_111A/String_Ops_Funcs.084.001.html#ww663456.

Case Expression

In both Teradata and SQL Server, there are two forms of CASE expressions:

  • The simple CASE expression compares an expression to a set of simple expressions to determine the result.
  • The searched CASE expression evaluates a set of Boolean expressions to determine the result.

Task

Retrieve the following information from Employee table:

  • EmployeeID,
  • EmployeeName,
  • Employee Salutation (if employee is Female, return ‘Dear MR + $EmployeeName' else return ‘Dear MS + $EmployeeName')

SQL – SQL Server

USE [TD_MS_SAMPLE_DB]
GO
SELECT Emp.EmployeeID, 
Emp.EmployeeName, 
CASE Emp.Gendar WHEN 'M' THEN 'Dear MR ' +Emp.EmployeeName ELSE 'Dear MS ' +Emp.EmployeeName END AS [Employee Salutation]
FROM dbo.Employee Emp;

SQL – Teradata

SELECT Emp.EmployeeID,
    Emp.EmployeeName,
    
    CASE
        WHEN  Emp.Gendar = 'M' THEN 'Dear MR ' || Emp.EmployeeName ELSE 'Dear MS ' ||Emp.EmployeeName
    END AS "Employee Salutation"
    FROM Employee Emp;

Result

image

Comments

The SQL Server sample is the simple version while the Teradata one is following the search format. If you want to evaluate columns with NULL value, you need to use the second format.

COALESCE

COALESCE is the ANSI standard function. Both SQL Server and Teradata support this function. The COALESCE function accepts a list of expressions as input and returns the first that is not NULL, or NULL if all are NULLs.

COALESCE(<exp1>, <exp2>, …, <expn>)

Task

Retrieve the employee id, employee name and manager employee id (display as characters) from Employee table; if there is no manger employee id, return ‘NULL’; the manager id needs to be displayed in the format ‘99,999’.

SQL – SQL Server

USE [TD_MS_SAMPLE_DB]
GO
SELECT Emp.EmployeeID, 
Emp.EmployeeName, 
COALESCE(FORMAT(Emp.EmployeeManagerEmployeeID, '##,###'),'NULL')  AS ManagerID
FROM dbo.Employee Emp;

SQL – Teradata

SELECT Emp.EmployeeID,
    Emp.EmployeeName,
    COALESCE((Emp.EmployeeManagerEmployeeID (FORMAT '99,999')),'NULL')  AS ManagerID
    FROM Employee Emp;

Result

image

ISNULL

There is no ISNULL equivalent function in Teradata and you need to use COALESCE.

For the previous example, the query can be rewritten using ISNULL in SQL Server.

SQL – SQL Server

USE [TD_MS_SAMPLE_DB]
GO
SELECT Emp.EmployeeID, 
Emp.EmployeeName, 
ISNULL(FORMAT(Emp.EmployeeManagerEmployeeID, '##,###'),'NULL')  AS ManagerID
FROM dbo.Employee Emp;

Comments

The nullability of the column can be different when using ISNULL compared with COALESCE in SQL Server. Please be careful when you use it as it may impact the execution plan significantly.

NULLIF

Bothe the two platforms supports NULLIF function.

NULLIF(col1, col2)

If col1 is equal to col2, the function returns a NULL; otherwise, it returns the col1 value.

Task

Retrieve the employee id, employee name and manager employee id (display as characters) from Employee table; if there the manger employee id is ‘10,004’, return ‘NULL’; the manager id needs to be displayed in the format ‘99,999’.

SQL – SQL Server

USE [TD_MS_SAMPLE_DB]
GO
SELECT Emp.EmployeeID, 
Emp.EmployeeName, 
NULLIF(FORMAT(Emp.EmployeeManagerEmployeeID, '##,###'),'10,004')  AS ManagerID
FROM dbo.Employee Emp;

SQL – Teradata

SELECT Emp.EmployeeID,
    Emp.EmployeeName,
    NULLIF((Emp.EmployeeManagerEmployeeID (FORMAT '99,999')),'10,004')  AS ManagerID
    FROM Employee Emp;

Result

image

Comments

There are some other useful variations in Teradata for NULL.

  • NULLIFZERO: This will change a zero value to a NULL value.
  • NULLIFSPACES: This will change a space value to a NULL value.
  • ZEROIFNULL: This will change a NULL value to a zero.

Summary

As both SQL Server and Teradata are following ANSI standards, you can easily convert your T-SQL to Teradata SQL and vice versa. It is recommended to use the ANSI standard functions/expressions so that you can migrate to each other smoothly.

In next tutorial, I will demonstrate the differences of filtering and sorting data.

More from Kontext
comment Comments
hide_source Anonymous

Mahe access_time 8 years ago link more_vert
Hello, I am having trouble using JPA to run Teradata queries. I am able to run the generated query in SQL Assistant but not from JPA. Below is the exception. com.ibm.db2.jcc.am.SqlSyntaxErrorException: DB2 SQL Error: SQLCODE=-204, SQLSTATE=42704, SQLERRMC=UY_DEV_DATA.EQ_EV_H, DRIVER=3.62.56 select equipevent0_.EQ_IN as EQ_INIT_1_13_, equipevent0_.EV_DT as EVENT_DT2_13_, equipevent0_.EV_TM as EVENT_TM3_13_, equipevent0_.EV_TYPE as EVENT_TY4_13_, equipevent0_.WB_N as WB_SN5_13_, equipevent0_.CI_NA_19 as CITY_NAM6_13_, equipevent0_.LO_EY as LOAD_EMP7_13_, equipevent0_.R_BL_TM_RD as RPT_BLK_8_13_, equipevent0_.SP as SPLC9_13_, equipevent0_.ST_PR_IN as STATE_P10_13_, equipevent0_.TR_B_N as TRANS_W11_13_ from UY_DEV_DATA.EQ_EV_H equipevent0_ where equipevent0_.EQ_IN = 'ABCD123456' and equipevent0_.WB_N = '654654' The query runs successfully in SQL Assist and the schema.table is valid too. Can you please help ? Thanks, Mahe
hide_source Anonymous

Raymond access_time 8 years ago link more_vert

@Mahe I could not identify any issue with your query directly.

Is your connection using the same credential as you were using in SQL Assistant?

hide_source Anonymous

Mahe access_time 8 years ago link more_vert
The alignment is all messed up in the comments. Sorry about that. BTW, its a VIEW select and not a TABLE
hide_source Anonymous

Eduardo Silva access_time 9 years ago link more_vert
Buenas tardes. En SQL utilizo el rigjht('nombre_columna',3) para rescatar una cierta cantidad de caracteres de una columna. Que sentencia deberia usar en TERADATA?
hide_source Anonymous

Raymond access_time 9 years ago link more_vert
@Eduardo Silva I am not sure whether I understand it correctly. There is non RIGHT function, so you have to use SUBSTR, for example, substr('nombre_columna', CHARACTER_LENGTH(nombre_columna)-2,3)
hide_source Anonymous

Martin access_time 9 years ago link more_vert
In part Character function, the second teradata query is wrong. UBSTRING(EmployeeName FROM 1 FOR 1) AS EmployeeNameLength, will give you in EmployeeNameLength column employee initials, the same like in EmployeeNameInitials
hide_source Anonymous

Raymond access_time 9 years ago link more_vert
@Martin Thanks for the correction Martin. The right query should be: SELECT Emp.EmployeeID, Emp.EmployeeName, LEN(EmployeeName) AS EmployeeNameLength, SUBSTRING(EmployeeName FROM 1 FOR 1) AS EmployeeNameInitials, CAST((Emp.JobGrade (FORMAT '9')) AS VARCHAR(1)) || ' - ' || CAST((Emp.Salary (FORMAT '9(3),999.99')) AS VARCHAR(13)) AS EmployeeJobGradeAndSalary FROM Employee Emp;

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